10(10)+x+0.01x^2=700

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Solution for 10(10)+x+0.01x^2=700 equation: 



10(10)+x+0.01x^2=700

We move all terms to the left:

10(10)+x+0.01x^2-(700)=0

We add all the numbers together, and all the variables

0.01x^2+x+310=0

a = 0.01; b = 1; c = +310;
Δ = b2-4ac
Δ = 12-4·0.01·310
Δ = -11.4
Delta is less than zero, so there is no solution for the equation

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